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13141303512242 = 26570651756121
BaseRepresentation
bin1011111100111011001010…
…1110100100110010110010
31201112022000000222200122212
42333032302232210302302
53210301342144342432
643541010445132122
72524266515550053
oct277166256446262
951468000880585
1013141303512242
11420721726a984
121582a57b5a042
137442b1614c19
1433608480a72a
1517bc7ea3e2b2
hexbf3b2ba4cb2

13141303512242 has 4 divisors (see below), whose sum is σ = 19711955268366. Its totient is φ = 6570651756120.

The previous prime is 13141303512229. The next prime is 13141303512251. The reversal of 13141303512242 is 24221530314131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8947331281681 + 4193972230561 = 2991209^2 + 2047919^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13141303512199 and 13141303512208.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285325878059 + ... + 3285325878062.

Almost surely, 213141303512242 is an apocalyptic number.

13141303512242 is a deficient number, since it is larger than the sum of its proper divisors (6570651756124).

13141303512242 is an equidigital number, since it uses as much as digits as its factorization.

13141303512242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6570651756123.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 13141303512242 its reverse (24221530314131), we get a palindrome (37362833826373).

The spelling of 13141303512242 in words is "thirteen trillion, one hundred forty-one billion, three hundred three million, five hundred twelve thousand, two hundred forty-two".

Divisors: 1 2 6570651756121 13141303512242