Base | Representation |
---|---|
bin | 11101111000010100001100… |
… | …110111111000110110110111 |
3 | 122020021222202221101011112211 |
4 | 131320110030313320312313 |
5 | 114211034000031124421 |
6 | 1143254241151554251 |
7 | 36452204555262451 |
oct | 3570241467706667 |
9 | 566258687334484 |
10 | 131413330333111 |
11 | 38966098042042 |
12 | 128a494a52b987 |
13 | 58432bab1c318 |
14 | 2464620d612d1 |
15 | 102d567b5b9e1 |
hex | 77850cdf8db7 |
131413330333111 has 2 divisors, whose sum is σ = 131413330333112. Its totient is φ = 131413330333110.
The previous prime is 131413330333067. The next prime is 131413330333147. The reversal of 131413330333111 is 111333033314131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131413330333111 - 213 = 131413330324919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131413330333511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706665166555 + 65706665166556.
It is an arithmetic number, because the mean of its divisors is an integer number (65706665166556).
Almost surely, 2131413330333111 is an apocalyptic number.
131413330333111 is a deficient number, since it is larger than the sum of its proper divisors (1).
131413330333111 is an equidigital number, since it uses as much as digits as its factorization.
131413330333111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 31.
Adding to 131413330333111 its reverse (111333033314131), we get a palindrome (242746363647242).
The spelling of 131413330333111 in words is "one hundred thirty-one trillion, four hundred thirteen billion, three hundred thirty million, three hundred thirty-three thousand, one hundred eleven".
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