Base | Representation |
---|---|
bin | 11000011110100100… |
… | …01111110001011011 |
3 | 1020220211202102001101 |
4 | 30033102033301123 |
5 | 203403140441243 |
6 | 10012000332231 |
7 | 643440401203 |
oct | 141722176133 |
9 | 36824672041 |
10 | 13141343323 |
11 | 5633a44819 |
12 | 2669014077 |
13 | 131575c5c4 |
14 | 8c943d403 |
15 | 51da7154d |
hex | 30f48fc5b |
13141343323 has 2 divisors, whose sum is σ = 13141343324. Its totient is φ = 13141343322.
The previous prime is 13141343321. The next prime is 13141343363. The reversal of 13141343323 is 32334314131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13141343323 - 21 = 13141343321 is a prime.
Together with 13141343321, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13141343291 and 13141343300.
It is not a weakly prime, because it can be changed into another prime (13141343321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570671661 + 6570671662.
It is an arithmetic number, because the mean of its divisors is an integer number (6570671662).
Almost surely, 213141343323 is an apocalyptic number.
13141343323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141343323 is an equidigital number, since it uses as much as digits as its factorization.
13141343323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7776, while the sum is 28.
Adding to 13141343323 its reverse (32334314131), we get a palindrome (45475657454).
The spelling of 13141343323 in words is "thirteen billion, one hundred forty-one million, three hundred forty-three thousand, three hundred twenty-three".
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