Base | Representation |
---|---|
bin | 11101111000010100110111… |
… | …010111000010000011100011 |
3 | 122020022001121121122112012221 |
4 | 131320110313113002003203 |
5 | 114211041430020442243 |
6 | 1143254440013531511 |
7 | 36452231332114546 |
oct | 3570246727020343 |
9 | 566261547575187 |
10 | 131414043140323 |
11 | 38966423439709 |
12 | 128a4b091a3b97 |
13 | 58433a26c3c38 |
14 | 246468b8b085d |
15 | 102d5aa50dbed |
hex | 7785375c20e3 |
131414043140323 has 2 divisors, whose sum is σ = 131414043140324. Its totient is φ = 131414043140322.
The previous prime is 131414043140291. The next prime is 131414043140351. The reversal of 131414043140323 is 323041340414131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131414043140323 - 25 = 131414043140291 is a prime.
It is not a weakly prime, because it can be changed into another prime (131414043140383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65707021570161 + 65707021570162.
It is an arithmetic number, because the mean of its divisors is an integer number (65707021570162).
Almost surely, 2131414043140323 is an apocalyptic number.
131414043140323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131414043140323 is an equidigital number, since it uses as much as digits as its factorization.
131414043140323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 131414043140323 its reverse (323041340414131), we get a palindrome (454455383554454).
The spelling of 131414043140323 in words is "one hundred thirty-one trillion, four hundred fourteen billion, forty-three million, one hundred forty thousand, three hundred twenty-three".
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