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131414450335 = 5759393116189
BaseRepresentation
bin111101001100011101…
…0010110000010011111
3110120012111110202201021
41322120322112002133
54123114044402320
6140212043425011
712331400253160
oct1723072260237
9416174422637
10131414450335
1150807038653
1221576525167
13c513c426ac
14650929d767
15364210edaa
hex1e98e9609f

131414450335 has 32 divisors (see below), whose sum is σ = 183338150400. Its totient is φ = 88557425280.

The previous prime is 131414450267. The next prime is 131414450381. The reversal of 131414450335 is 533054414131.

It is not a de Polignac number, because 131414450335 - 221 = 131412353183 is a prime.

It is a super-2 number, since 2×1314144503352 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131414450335.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8109421 + ... + 8125609.

It is an arithmetic number, because the mean of its divisors is an integer number (5729317200).

Almost surely, 2131414450335 is an apocalyptic number.

131414450335 is a deficient number, since it is larger than the sum of its proper divisors (51923700065).

131414450335 is a wasteful number, since it uses less digits than its factorization.

131414450335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20191.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 131414450335 its reverse (533054414131), we get a palindrome (664468864466).

The spelling of 131414450335 in words is "one hundred thirty-one billion, four hundred fourteen million, four hundred fifty thousand, three hundred thirty-five".

Divisors: 1 5 7 35 59 295 413 2065 3931 16189 19655 27517 80945 113323 137585 231929 566615 955151 1159645 1623503 4775755 6686057 8117515 33430285 63638959 318194795 445472713 2227363565 3754698581 18773492905 26282890067 131414450335