Base | Representation |
---|---|
bin | 1011111100111011101111… |
… | …0000011111101001100011 |
3 | 1201112022101121001121001212 |
4 | 2333032323300133221203 |
5 | 3210302144440313103 |
6 | 43541033500220335 |
7 | 2524303335346466 |
oct | 277167360375143 |
9 | 51468347047055 |
10 | 13141455010403 |
11 | 4207294835775 |
12 | 1582a9a83a6ab |
13 | 744306b199c5 |
14 | 33609a9a52dd |
15 | 17bc8ceb77d8 |
hex | bf3bbc1fa63 |
13141455010403 has 2 divisors, whose sum is σ = 13141455010404. Its totient is φ = 13141455010402.
The previous prime is 13141455010399. The next prime is 13141455010433. The reversal of 13141455010403 is 30401055414131.
It is a weak prime.
It is an emirp because it is prime and its reverse (30401055414131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13141455010403 - 22 = 13141455010399 is a prime.
It is a super-2 number, since 2×131414550104032 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13141455010403.
It is not a weakly prime, because it can be changed into another prime (13141455010433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570727505201 + 6570727505202.
It is an arithmetic number, because the mean of its divisors is an integer number (6570727505202).
Almost surely, 213141455010403 is an apocalyptic number.
13141455010403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141455010403 is an equidigital number, since it uses as much as digits as its factorization.
13141455010403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 32.
The spelling of 13141455010403 in words is "thirteen trillion, one hundred forty-one billion, four hundred fifty-five million, ten thousand, four hundred three".
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