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131414915441 is a prime number
BaseRepresentation
bin111101001100011110…
…0000111100101110001
3110120012112100101201102
41322120330013211301
54123114204243231
6140212101414145
712331404231155
oct1723074074561
9416175311642
10131414915441
1150807326037
122157670a355
13c5140762c4
146509381065
1536421a2acb
hex1e98f07971

131414915441 has 2 divisors, whose sum is σ = 131414915442. Its totient is φ = 131414915440.

The previous prime is 131414915413. The next prime is 131414915453. The reversal of 131414915441 is 144519414131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83003914816 + 48411000625 = 288104^2 + 220025^2 .

It is an emirp because it is prime and its reverse (144519414131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131414915441 - 218 = 131414653297 is a prime.

It is a super-3 number, since 3×1314149154413 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131414915395 and 131414915404.

It is not a weakly prime, because it can be changed into another prime (131414915041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65707457720 + 65707457721.

It is an arithmetic number, because the mean of its divisors is an integer number (65707457721).

Almost surely, 2131414915441 is an apocalyptic number.

It is an amenable number.

131414915441 is a deficient number, since it is larger than the sum of its proper divisors (1).

131414915441 is an equidigital number, since it uses as much as digits as its factorization.

131414915441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34560, while the sum is 38.

The spelling of 131414915441 in words is "one hundred thirty-one billion, four hundred fourteen million, nine hundred fifteen thousand, four hundred forty-one".