Base | Representation |
---|---|
bin | 11101111000011010110100… |
… | …110100101100001011010111 |
3 | 122020022200010122011211100012 |
4 | 131320122310310230023113 |
5 | 114211143031404044302 |
6 | 1143301415033510435 |
7 | 36452546043243626 |
oct | 3570326464541327 |
9 | 566280118154305 |
10 | 131420443034327 |
11 | 38969107a72807 |
12 | 128a61b457241b |
13 | 5843b82594c75 |
14 | 2464ad78576bd |
15 | 102d8322d8a52 |
hex | 7786b4d2c2d7 |
131420443034327 has 2 divisors, whose sum is σ = 131420443034328. Its totient is φ = 131420443034326.
The previous prime is 131420443034299. The next prime is 131420443034347. The reversal of 131420443034327 is 723430344024131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131420443034327 - 28 = 131420443034071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131420443034347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65710221517163 + 65710221517164.
It is an arithmetic number, because the mean of its divisors is an integer number (65710221517164).
Almost surely, 2131420443034327 is an apocalyptic number.
131420443034327 is a deficient number, since it is larger than the sum of its proper divisors (1).
131420443034327 is an equidigital number, since it uses as much as digits as its factorization.
131420443034327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 580608, while the sum is 41.
Adding to 131420443034327 its reverse (723430344024131), we get a palindrome (854850787058458).
The spelling of 131420443034327 in words is "one hundred thirty-one trillion, four hundred twenty billion, four hundred forty-three million, thirty-four thousand, three hundred twenty-seven".
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