Base | Representation |
---|---|
bin | 1011111100111110001000… |
… | …1110100010011000110111 |
3 | 1201112101001120111210210121 |
4 | 2333033202032202120313 |
5 | 3210310010201421101 |
6 | 43541221513432411 |
7 | 2524325333264533 |
oct | 277174216423067 |
9 | 51471046453717 |
10 | 13142100420151 |
11 | 420759608965a |
12 | 158303aa0b707 |
13 | 7443aa754571 |
14 | 33611c5acbc3 |
15 | 17bcc99a50a1 |
hex | bf3e23a2637 |
13142100420151 has 4 divisors (see below), whose sum is σ = 13155073866792. Its totient is φ = 13129126973512.
The previous prime is 13142100420109. The next prime is 13142100420187. The reversal of 13142100420151 is 15102400124131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13142100420151 - 227 = 13141966202423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13142100420451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6486721801 + ... + 6486723826.
It is an arithmetic number, because the mean of its divisors is an integer number (3288768466698).
Almost surely, 213142100420151 is an apocalyptic number.
13142100420151 is a deficient number, since it is larger than the sum of its proper divisors (12973446641).
13142100420151 is a wasteful number, since it uses less digits than its factorization.
13142100420151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12973446640.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 13142100420151 its reverse (15102400124131), we get a palindrome (28244500544282).
The spelling of 13142100420151 in words is "thirteen trillion, one hundred forty-two billion, one hundred million, four hundred twenty thousand, one hundred fifty-one".
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