131421102040 has 16 divisors (see below), whose sum is σ = 295697479680. Its totient is φ = 52568440800.

The previous prime is 131421102017. The next prime is 131421102041. The reversal of 131421102040 is 40201124131.

It is a super-2 number, since 2×131421102040² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131421101999 and 131421102017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131421102041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1642763736 + ... + 1642763815.

It is an arithmetic number, because the mean of its divisors is an integer number (18481092480).

Almost surely, 2^131421102040 is an apocalyptic number.

131421102040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131421102040 is an abundant number, since it is smaller than the sum of its proper divisors (164276377640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131421102040 is a wasteful number, since it uses less digits than its factorization.

131421102040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3285527562 (or 3285527558 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 131421102040 its reverse (40201124131), we get a palindrome (171622226171).

The spelling of 131421102040 in words is "one hundred thirty-one billion, four hundred twenty-one million, one hundred two thousand, forty".