131421123241330 has 32 divisors (see below), whose sum is σ = 254769362059968. Its totient is φ = 48521947320000.

The previous prime is 131421123241271. The next prime is 131421123241367. The reversal of 131421123241330 is 33142321124131.

It is a junction number, because it is equal to n+sod(n) for n = 131421123241292 and 131421123241301.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26624796 + ... + 31172455.

It is an arithmetic number, because the mean of its divisors is an integer number (7961542564374).

Almost surely, 2^{131421123241330} is an apocalyptic number.

131421123241330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131421123241330 is a deficient number, since it is larger than the sum of its proper divisors (123348238818638).

131421123241330 is a wasteful number, since it uses less digits than its factorization.

131421123241330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57814762.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131421123241330 its reverse (33142321124131), we get a palindrome (164563444365461).

The spelling of 131421123241330 in words is "one hundred thirty-one trillion, four hundred twenty-one billion, one hundred twenty-three million, two hundred forty-one thousand, three hundred thirty".