Base | Representation |
---|---|
bin | 1011111100111110001110… |
… | …0110010100001000001010 |
3 | 1201112101010011210211221102 |
4 | 2333033203212110020022 |
5 | 3210310032044233120 |
6 | 43541224054541402 |
7 | 2524326033002042 |
oct | 277174346241012 |
9 | 51471104724842 |
10 | 13142123430410 |
11 | 42075a80755a7 |
12 | 1583046667862 |
13 | 7443b244cbc0 |
14 | 33612167c722 |
15 | 17bccb9ecd75 |
hex | bf3e399420a |
13142123430410 has 32 divisors (see below), whose sum is σ = 25797975517440. Its totient is φ = 4791052588608.
The previous prime is 13142123430367. The next prime is 13142123430437. The reversal of 13142123430410 is 1403432124131.
13142123430410 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131421234304102 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 639820472 + ... + 639841011.
It is an arithmetic number, because the mean of its divisors is an integer number (806186734920).
Almost surely, 213142123430410 is an apocalyptic number.
13142123430410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13142123430410 is a deficient number, since it is larger than the sum of its proper divisors (12655852087030).
13142123430410 is a wasteful number, since it uses less digits than its factorization.
13142123430410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1279661582.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13142123430410 its reverse (1403432124131), we get a palindrome (14545555554541).
The spelling of 13142123430410 in words is "thirteen trillion, one hundred forty-two billion, one hundred twenty-three million, four hundred thirty thousand, four hundred ten".
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