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13142224452517 is a prime number
BaseRepresentation
bin1011111100111110100110…
…0111101011101110100101
31201112101101012220022012221
42333033221213223232211
53210310233424440032
643541242104112341
72524331400452116
oct277175147535645
951471335808187
1013142224452517
11420764a0a4a46
1215830744656b1
137443ca3609b4
14336130c5820d
1517bcd5805597
hexbf3e99ebba5

13142224452517 has 2 divisors, whose sum is σ = 13142224452518. Its totient is φ = 13142224452516.

The previous prime is 13142224452503. The next prime is 13142224452527. The reversal of 13142224452517 is 71525442224131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12272977764961 + 869246687556 = 3503281^2 + 932334^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142224452517 - 227 = 13142090234789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13142224452527) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571112226258 + 6571112226259.

It is an arithmetic number, because the mean of its divisors is an integer number (6571112226259).

Almost surely, 213142224452517 is an apocalyptic number.

It is an amenable number.

13142224452517 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142224452517 is an equidigital number, since it uses as much as digits as its factorization.

13142224452517 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 537600, while the sum is 43.

Adding to 13142224452517 its reverse (71525442224131), we get a palindrome (84667666676648).

The spelling of 13142224452517 in words is "thirteen trillion, one hundred forty-two billion, two hundred twenty-four million, four hundred fifty-two thousand, five hundred seventeen".