Base | Representation |
---|---|
bin | 11101111000011100101011… |
… | …111110010101101010101111 |
3 | 122020022212021221200110102211 |
4 | 131320130223332111222233 |
5 | 114211211130131133041 |
6 | 1143302345243431251 |
7 | 36452646425515366 |
oct | 3570345376255257 |
9 | 566285257613384 |
10 | 131422442052271 |
11 | 38969a433a9557 |
12 | 128a6671b25527 |
13 | 5844110787316 |
14 | 2464c471387dd |
15 | 102d8eca55481 |
hex | 77872bf95aaf |
131422442052271 has 2 divisors, whose sum is σ = 131422442052272. Its totient is φ = 131422442052270.
The previous prime is 131422442052217. The next prime is 131422442052401. The reversal of 131422442052271 is 172250244224131.
Together with previous prime (131422442052217) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131422442052271 - 219 = 131422441527983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131422442055271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711221026135 + 65711221026136.
It is an arithmetic number, because the mean of its divisors is an integer number (65711221026136).
Almost surely, 2131422442052271 is an apocalyptic number.
131422442052271 is a deficient number, since it is larger than the sum of its proper divisors (1).
131422442052271 is an equidigital number, since it uses as much as digits as its factorization.
131422442052271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 215040, while the sum is 40.
The spelling of 131422442052271 in words is "one hundred thirty-one trillion, four hundred twenty-two billion, four hundred forty-two million, fifty-two thousand, two hundred seventy-one".
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