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13142310531473 is a prime number
BaseRepresentation
bin1011111100111110111011…
…0000000011000110010001
31201112101121012212120100102
42333033232300003012101
53210310422444001343
643541254421102145
72524333464224144
oct277175660030621
951471535776312
1013142310531473
114207693748382
121583099257955
1374441213bca6
1433613c46405b
1517bcdd15a3b8
hexbf3eec03191

13142310531473 has 2 divisors, whose sum is σ = 13142310531474. Its totient is φ = 13142310531472.

The previous prime is 13142310531421. The next prime is 13142310531523. The reversal of 13142310531473 is 37413501324131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13125020385409 + 17290146064 = 3622847^2 + 131492^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142310531473 - 234 = 13125130662289 is a prime.

It is a super-3 number, since 3×131423105314733 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13142310551473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571155265736 + 6571155265737.

It is an arithmetic number, because the mean of its divisors is an integer number (6571155265737).

Almost surely, 213142310531473 is an apocalyptic number.

It is an amenable number.

13142310531473 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142310531473 is an equidigital number, since it uses as much as digits as its factorization.

13142310531473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 38.

The spelling of 13142310531473 in words is "thirteen trillion, one hundred forty-two billion, three hundred ten million, five hundred thirty-one thousand, four hundred seventy-three".