Base | Representation |
---|---|
bin | 1011111100111111000010… |
… | …1000100011111100101111 |
3 | 1201112101200102022121012111 |
4 | 2333033300220203330233 |
5 | 3210311004040421221 |
6 | 43541301510144451 |
7 | 2524334326602502 |
oct | 277176050437457 |
9 | 51471612277174 |
10 | 13142342123311 |
11 | 42076aa565835 |
12 | 15830a7952127 |
13 | 74441885069b |
14 | 336142729139 |
15 | 17bce0ceabe1 |
hex | bf3f0a23f2f |
13142342123311 has 2 divisors, whose sum is σ = 13142342123312. Its totient is φ = 13142342123310.
The previous prime is 13142342123237. The next prime is 13142342123329. The reversal of 13142342123311 is 11332124324131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13142342123311 - 211 = 13142342121263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13142342123381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571171061655 + 6571171061656.
It is an arithmetic number, because the mean of its divisors is an integer number (6571171061656).
Almost surely, 213142342123311 is an apocalyptic number.
13142342123311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142342123311 is an equidigital number, since it uses as much as digits as its factorization.
13142342123311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 31.
Adding to 13142342123311 its reverse (11332124324131), we get a palindrome (24474466447442).
The spelling of 13142342123311 in words is "thirteen trillion, one hundred forty-two billion, three hundred forty-two million, one hundred twenty-three thousand, three hundred eleven".
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