Base | Representation |
---|---|
bin | 11000011110101100… |
… | …00100010100101000 |
3 | 1020220220122022002112 |
4 | 30033112010110220 |
5 | 203403420020000 |
6 | 10012034021452 |
7 | 643452042431 |
oct | 141726042450 |
9 | 36826568075 |
10 | 13142345000 |
11 | 5634569354 |
12 | 2669417888 |
13 | 1315a20505 |
14 | 8c9620488 |
15 | 51dbbd235 |
hex | 30f584528 |
13142345000 has 80 divisors (see below), whose sum is σ = 31544043300. Its totient is φ = 5128640000.
The previous prime is 13142344993. The next prime is 13142345063. The reversal of 13142345000 is 54324131.
It can be written as a sum of positive squares in 10 ways, for example, as 585349636 + 12556995364 = 24194^2 + 112058^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 172946 + ... + 237054.
Almost surely, 213142345000 is an apocalyptic number.
13142345000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13142345000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15772021650).
13142345000 is an abundant number, since it is smaller than the sum of its proper divisors (18401698300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142345000 is an equidigital number, since it uses as much as digits as its factorization.
13142345000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64176 (or 64157 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 13142345000 its reverse (54324131), we get a palindrome (13196669131).
The spelling of 13142345000 in words is "thirteen billion, one hundred forty-two million, three hundred forty-five thousand".
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