Base | Representation |
---|---|
bin | 1011111100111111010011… |
… | …0111000100000010010011 |
3 | 1201112101212100202012212012 |
4 | 2333033310313010002103 |
5 | 3210311130214033434 |
6 | 43541312522053135 |
7 | 2524336150410212 |
oct | 277176467040223 |
9 | 51471770665765 |
10 | 13142413033619 |
11 | 42077365987a1 |
12 | 158310764a1ab |
13 | 74442a44a64c |
14 | 33614bd07079 |
15 | 17bce71563ce |
hex | bf3f4dc4093 |
13142413033619 has 2 divisors, whose sum is σ = 13142413033620. Its totient is φ = 13142413033618.
The previous prime is 13142413033609. The next prime is 13142413033661. The reversal of 13142413033619 is 91633031424131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13142413033619 - 232 = 13138118066323 is a prime.
It is a super-3 number, since 3×131424130336193 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13142413033609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571206516809 + 6571206516810.
It is an arithmetic number, because the mean of its divisors is an integer number (6571206516810).
Almost surely, 213142413033619 is an apocalyptic number.
13142413033619 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142413033619 is an equidigital number, since it uses as much as digits as its factorization.
13142413033619 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 41.
The spelling of 13142413033619 in words is "thirteen trillion, one hundred forty-two billion, four hundred thirteen million, thirty-three thousand, six hundred nineteen".
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