Base | Representation |
---|---|
bin | 1011111100111111010011… |
… | …0111000100001001011101 |
3 | 1201112101212100202020111011 |
4 | 2333033310313010021131 |
5 | 3210311130214042302 |
6 | 43541312522055221 |
7 | 2524336150411435 |
oct | 277176467041135 |
9 | 51471770666434 |
10 | 13142413034077 |
11 | 4207736599078 |
12 | 158310764a511 |
13 | 74442a44a912 |
14 | 33614bd072c5 |
15 | 17bce71565d7 |
hex | bf3f4dc425d |
13142413034077 has 2 divisors, whose sum is σ = 13142413034078. Its totient is φ = 13142413034076.
The previous prime is 13142413034057. The next prime is 13142413034137. The reversal of 13142413034077 is 77043031424131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6840636242521 + 6301776791556 = 2615461^2 + 2510334^2 .
It is an emirp because it is prime and its reverse (77043031424131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13142413034077 - 215 = 13142413001309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13142413034057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571206517038 + 6571206517039.
It is an arithmetic number, because the mean of its divisors is an integer number (6571206517039).
Almost surely, 213142413034077 is an apocalyptic number.
It is an amenable number.
13142413034077 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142413034077 is an equidigital number, since it uses as much as digits as its factorization.
13142413034077 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 169344, while the sum is 40.
The spelling of 13142413034077 in words is "thirteen trillion, one hundred forty-two billion, four hundred thirteen million, thirty-four thousand, seventy-seven".
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