Base | Representation |
---|---|
bin | 11101111000011110010111… |
… | …111111010000001111001111 |
3 | 122020100000222020121201000011 |
4 | 131320132113333100033033 |
5 | 114211223333040402003 |
6 | 1143303245141014051 |
7 | 36453042352006642 |
oct | 3570362777201717 |
9 | 566300866551004 |
10 | 131424254231503 |
11 | 3896a793321642 |
12 | 128a6a989b4327 |
13 | 584433c04cb1c |
14 | 2464d79aa1a59 |
15 | 102d9a6bb746d |
hex | 778797fd03cf |
131424254231503 has 2 divisors, whose sum is σ = 131424254231504. Its totient is φ = 131424254231502.
The previous prime is 131424254231489. The next prime is 131424254231521. The reversal of 131424254231503 is 305132452424131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131424254231503 - 217 = 131424254100431 is a prime.
It is a super-2 number, since 2×1314242542315032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131424254231533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712127115751 + 65712127115752.
It is an arithmetic number, because the mean of its divisors is an integer number (65712127115752).
Almost surely, 2131424254231503 is an apocalyptic number.
131424254231503 is a deficient number, since it is larger than the sum of its proper divisors (1).
131424254231503 is an equidigital number, since it uses as much as digits as its factorization.
131424254231503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 40.
The spelling of 131424254231503 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, two hundred fifty-four million, two hundred thirty-one thousand, five hundred three".
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