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131424254231503 is a prime number
BaseRepresentation
bin11101111000011110010111…
…111111010000001111001111
3122020100000222020121201000011
4131320132113333100033033
5114211223333040402003
61143303245141014051
736453042352006642
oct3570362777201717
9566300866551004
10131424254231503
113896a793321642
12128a6a989b4327
13584433c04cb1c
142464d79aa1a59
15102d9a6bb746d
hex778797fd03cf

131424254231503 has 2 divisors, whose sum is σ = 131424254231504. Its totient is φ = 131424254231502.

The previous prime is 131424254231489. The next prime is 131424254231521. The reversal of 131424254231503 is 305132452424131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131424254231503 - 217 = 131424254100431 is a prime.

It is a super-2 number, since 2×1314242542315032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131424254231533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712127115751 + 65712127115752.

It is an arithmetic number, because the mean of its divisors is an integer number (65712127115752).

Almost surely, 2131424254231503 is an apocalyptic number.

131424254231503 is a deficient number, since it is larger than the sum of its proper divisors (1).

131424254231503 is an equidigital number, since it uses as much as digits as its factorization.

131424254231503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 345600, while the sum is 40.

The spelling of 131424254231503 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, two hundred fifty-four million, two hundred thirty-one thousand, five hundred three".