1314252041130 has 48 divisors (see below), whose sum is σ = 3905206066944. Its totient is φ = 300400466400.

The previous prime is 1314252041117. The next prime is 1314252041131. The reversal of 1314252041130 is 311402524131.

1314252041130 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 2 + 520 + 4 + 1 + 130 = 666.

It is a super-2 number, since 2×1314252041130² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314252041094 and 1314252041103.

It is not an unprimeable number, because it can be changed into a prime (1314252041131) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1043056546 + ... + 1043057805.

It is an arithmetic number, because the mean of its divisors is an integer number (81358459728).

Almost surely, 2^{1314252041130} is an apocalyptic number.

1314252041130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1314252041130 is an abundant number, since it is smaller than the sum of its proper divisors (2590954025814).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1314252041130 is a wasteful number, since it uses less digits than its factorization.

1314252041130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2086114371 (or 2086114368 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 1314252041130 its reverse (311402524131), we get a palindrome (1625654565261).

The spelling of 1314252041130 in words is "one trillion, three hundred fourteen billion, two hundred fifty-two million, forty-one thousand, one hundred thirty".