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1314302111 is a prime number
BaseRepresentation
bin100111001010110…
…1010100010011111
310101121002110112222
41032111222202133
510142430131421
6334230015555
744366245403
oct11625524237
93347073488
101314302111
116149866a1
123081a75bb
1317c3a4a75
14c67a5103
157a5b7cab
hex4e56a89f

1314302111 has 2 divisors, whose sum is σ = 1314302112. Its totient is φ = 1314302110.

The previous prime is 1314302081. The next prime is 1314302117. The reversal of 1314302111 is 1112034131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1314302111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1314302111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314302117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657151055 + 657151056.

It is an arithmetic number, because the mean of its divisors is an integer number (657151056).

Almost surely, 21314302111 is an apocalyptic number.

1314302111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314302111 is an equidigital number, since it uses as much as digits as its factorization.

1314302111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1314302111 is about 36253.3048286636. The cubic root of 1314302111 is about 1095.3806592700.

Adding to 1314302111 its reverse (1112034131), we get a palindrome (2426336242).

The spelling of 1314302111 in words is "one billion, three hundred fourteen million, three hundred two thousand, one hundred eleven".