13143101219 has 2 divisors, whose sum is σ = 13143101220. Its totient is φ = 13143101218.

The previous prime is 13143101161. The next prime is 13143101221. The reversal of 13143101219 is 91210134131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13143101219 - 2⁸ = 13143100963 is a prime.

It is a super-2 number, since 2×13143101219² (a number of 21 digits) contains 22 as substring.

Together with 13143101221, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13143101119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571550609 + 6571550610.

It is an arithmetic number, because the mean of its divisors is an integer number (6571550610).

Almost surely, 2^13143101219 is an apocalyptic number.

13143101219 is a deficient number, since it is larger than the sum of its proper divisors (1).

13143101219 is an equidigital number, since it uses as much as digits as its factorization.

13143101219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 26.

The spelling of 13143101219 in words is "thirteen billion, one hundred forty-three million, one hundred one thousand, two hundred nineteen".