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1314311402423 is a prime number
BaseRepresentation
bin10011001000000011000…
…100000111001110110111
311122122110121210000121202
4103020003010013032313
5133013202204334143
62443441502403115
7163645601406605
oct23100304071667
94578417700552
101314311402423
1146743a5826a8
1219288029049b
1396c290970b6
1447882162875
15242c556aab8
hex132031073b7

1314311402423 has 2 divisors, whose sum is σ = 1314311402424. Its totient is φ = 1314311402422.

The previous prime is 1314311402407. The next prime is 1314311402431. The reversal of 1314311402423 is 3242041134131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3242041134131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1314311402423 - 24 = 1314311402407 is a prime.

It is a super-2 number, since 2×13143114024232 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314311402623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657155701211 + 657155701212.

It is an arithmetic number, because the mean of its divisors is an integer number (657155701212).

Almost surely, 21314311402423 is an apocalyptic number.

1314311402423 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314311402423 is an equidigital number, since it uses as much as digits as its factorization.

1314311402423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1314311402423 its reverse (3242041134131), we get a palindrome (4556352536554).

The spelling of 1314311402423 in words is "one trillion, three hundred fourteen billion, three hundred eleven million, four hundred two thousand, four hundred twenty-three".