Base | Representation |
---|---|
bin | 10011001000000011000… |
… | …100000111001110110111 |
3 | 11122122110121210000121202 |
4 | 103020003010013032313 |
5 | 133013202204334143 |
6 | 2443441502403115 |
7 | 163645601406605 |
oct | 23100304071667 |
9 | 4578417700552 |
10 | 1314311402423 |
11 | 46743a5826a8 |
12 | 19288029049b |
13 | 96c290970b6 |
14 | 47882162875 |
15 | 242c556aab8 |
hex | 132031073b7 |
1314311402423 has 2 divisors, whose sum is σ = 1314311402424. Its totient is φ = 1314311402422.
The previous prime is 1314311402407. The next prime is 1314311402431. The reversal of 1314311402423 is 3242041134131.
It is a strong prime.
It is an emirp because it is prime and its reverse (3242041134131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1314311402423 - 24 = 1314311402407 is a prime.
It is a super-2 number, since 2×13143114024232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314311402623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657155701211 + 657155701212.
It is an arithmetic number, because the mean of its divisors is an integer number (657155701212).
Almost surely, 21314311402423 is an apocalyptic number.
1314311402423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314311402423 is an equidigital number, since it uses as much as digits as its factorization.
1314311402423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1314311402423 its reverse (3242041134131), we get a palindrome (4556352536554).
The spelling of 1314311402423 in words is "one trillion, three hundred fourteen billion, three hundred eleven million, four hundred two thousand, four hundred twenty-three".
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