Base | Representation |
---|---|
bin | 1011111101000010000100… |
… | …1101011101100110111111 |
3 | 1201112110210012211212012212 |
4 | 2333100201031131212333 |
5 | 3210314141204244124 |
6 | 43541514422051035 |
7 | 2524363454035625 |
oct | 277204115354677 |
9 | 51473705755185 |
10 | 13143157103039 |
11 | 4207a885a80a7 |
12 | 1583294879a7b |
13 | 744518649902 |
14 | 3361bca73515 |
15 | 17bd3c63140e |
hex | bf42135d9bf |
13143157103039 has 2 divisors, whose sum is σ = 13143157103040. Its totient is φ = 13143157103038.
The previous prime is 13143157103023. The next prime is 13143157103137. The reversal of 13143157103039 is 93030175134131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13143157103039 - 24 = 13143157103023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13143157102987 and 13143157103005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13143157103009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571578551519 + 6571578551520.
It is an arithmetic number, because the mean of its divisors is an integer number (6571578551520).
Almost surely, 213143157103039 is an apocalyptic number.
13143157103039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143157103039 is an equidigital number, since it uses as much as digits as its factorization.
13143157103039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 102060, while the sum is 41.
The spelling of 13143157103039 in words is "thirteen trillion, one hundred forty-three billion, one hundred fifty-seven million, one hundred three thousand, thirty-nine".
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