Base | Representation |
---|---|
bin | 1011111101000010010110… |
… | …1001010001110101000011 |
3 | 1201112110222101211210201021 |
4 | 2333100211221101311003 |
5 | 3210314314231104213 |
6 | 43541530040450311 |
7 | 2524365346321261 |
oct | 277204551216503 |
9 | 51473871753637 |
10 | 13143231503683 |
11 | 42080165a4436 |
12 | 15832b5779997 |
13 | 74452ab99468 |
14 | 3361c88bd431 |
15 | 17bd43e2ad8d |
hex | bf425a51d43 |
13143231503683 has 2 divisors, whose sum is σ = 13143231503684. Its totient is φ = 13143231503682.
The previous prime is 13143231503531. The next prime is 13143231503711. The reversal of 13143231503683 is 38630513234131.
It is a happy number.
13143231503683 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13143231503683 is a prime.
It is not a weakly prime, because it can be changed into another prime (13143231500683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571615751841 + 6571615751842.
It is an arithmetic number, because the mean of its divisors is an integer number (6571615751842).
Almost surely, 213143231503683 is an apocalyptic number.
13143231503683 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143231503683 is an equidigital number, since it uses as much as digits as its factorization.
13143231503683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 43.
The spelling of 13143231503683 in words is "thirteen trillion, one hundred forty-three billion, two hundred thirty-one million, five hundred three thousand, six hundred eighty-three".
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