Base | Representation |
---|---|
bin | 1011111101000010100111… |
… | …0000101100000110001101 |
3 | 1201112111011012202222111222 |
4 | 2333100221300230012031 |
5 | 3210314434420231044 |
6 | 43541540544453125 |
7 | 2524400145254432 |
oct | 277205160540615 |
9 | 51474135688458 |
10 | 13143300555149 |
11 | 4208051577866 |
12 | 158331491a1a5 |
13 | 74453c29530b |
14 | 3361d3b35b89 |
15 | 17bd4a01a8ee |
hex | bf429c2c18d |
13143300555149 has 2 divisors, whose sum is σ = 13143300555150. Its totient is φ = 13143300555148.
The previous prime is 13143300555113. The next prime is 13143300555169. The reversal of 13143300555149 is 94155500334131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11521320010249 + 1621980544900 = 3394307^2 + 1273570^2 .
It is a cyclic number.
It is not a de Polignac number, because 13143300555149 - 212 = 13143300551053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13143300555169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571650277574 + 6571650277575.
It is an arithmetic number, because the mean of its divisors is an integer number (6571650277575).
Almost surely, 213143300555149 is an apocalyptic number.
It is an amenable number.
13143300555149 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143300555149 is an equidigital number, since it uses as much as digits as its factorization.
13143300555149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486000, while the sum is 44.
The spelling of 13143300555149 in words is "thirteen trillion, one hundred forty-three billion, three hundred million, five hundred fifty-five thousand, one hundred forty-nine".
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