Base | Representation |
---|---|
bin | 11101111000100110100111… |
… | …010000011010110111001100 |
3 | 122020100212210202002210000201 |
4 | 131320212213100122313030 |
5 | 114211344442140334200 |
6 | 1143311311023303244 |
7 | 36453504515365645 |
oct | 3570464720326714 |
9 | 566325722083021 |
10 | 131433100324300 |
11 | 38973512752035 |
12 | 128a874744ab24 |
13 | 584511b963968 |
14 | 24655788926cc |
15 | 102dd235e1c6a |
hex | 7789a741adcc |
131433100324300 has 72 divisors (see below), whose sum is σ = 289121174748000. Its totient is φ = 51852276241920.
The previous prime is 131433100324271. The next prime is 131433100324333. The reversal of 131433100324300 is 3423001334131.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 836494146 + ... + 836651254.
It is an arithmetic number, because the mean of its divisors is an integer number (4015571871500).
Almost surely, 2131433100324300 is an apocalyptic number.
131433100324300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131433100324300 is an abundant number, since it is smaller than the sum of its proper divisors (157688074423700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131433100324300 is a wasteful number, since it uses less digits than its factorization.
131433100324300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 271795 (or 271788 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 131433100324300 its reverse (3423001334131), we get a palindrome (134856101658431).
The spelling of 131433100324300 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, one hundred million, three hundred twenty-four thousand, three hundred".
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