131433100324441 has 2 divisors, whose sum is σ = 131433100324442. Its totient is φ = 131433100324440.

The previous prime is 131433100324333. The next prime is 131433100324541. The reversal of 131433100324441 is 144423001334131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110570167105225 + 20862933219216 = 10515235^2 + 4567596^2 .

It is a cyclic number.

It is not a de Polignac number, because 131433100324441 - 2²³ = 131433091935833 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131433100324397 and 131433100324406.

It is not a weakly prime, because it can be changed into another prime (131433100324541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65716550162220 + 65716550162221.

It is an arithmetic number, because the mean of its divisors is an integer number (65716550162221).

Almost surely, 2^{131433100324441} is an apocalyptic number.

It is an amenable number.

131433100324441 is a deficient number, since it is larger than the sum of its proper divisors (1).

131433100324441 is an equidigital number, since it uses as much as digits as its factorization.

131433100324441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 131433100324441 its reverse (144423001334131), we get a palindrome (275856101658572).

The spelling of 131433100324441 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, one hundred million, three hundred twenty-four thousand, four hundred forty-one".