Base | Representation |
---|---|
bin | 11101111000100110101101… |
… | …001110010110000001001111 |
3 | 122020100220001201111100201011 |
4 | 131320212231032112001033 |
5 | 114211400143303142341 |
6 | 1143311325001230051 |
7 | 36453510142365403 |
oct | 3570465516260117 |
9 | 566326051440634 |
10 | 131433200443471 |
11 | 38973564215053 |
12 | 128a8774a92327 |
13 | 5845136619784 |
14 | 2465587cb5103 |
15 | 102dd2c2bbb81 |
hex | 7789ad39604f |
131433200443471 has 2 divisors, whose sum is σ = 131433200443472. Its totient is φ = 131433200443470.
The previous prime is 131433200443327. The next prime is 131433200443499. The reversal of 131433200443471 is 174344002334131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131433200443471 - 219 = 131433199919183 is a prime.
It is a super-3 number, since 3×1314332004434713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131433200443271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65716600221735 + 65716600221736.
It is an arithmetic number, because the mean of its divisors is an integer number (65716600221736).
Almost surely, 2131433200443471 is an apocalyptic number.
131433200443471 is a deficient number, since it is larger than the sum of its proper divisors (1).
131433200443471 is an equidigital number, since it uses as much as digits as its factorization.
131433200443471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 290304, while the sum is 40.
The spelling of 131433200443471 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, two hundred million, four hundred forty-three thousand, four hundred seventy-one".
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