Base | Representation |
---|---|
bin | 11101111000100111101010… |
… | …100110001100010111001111 |
3 | 122020100222201110222121112202 |
4 | 131320213222212030113033 |
5 | 114211404300401334201 |
6 | 1143312015102352115 |
7 | 36453544514356562 |
oct | 3570475246142717 |
9 | 566328643877482 |
10 | 131434230105551 |
11 | 38973a4245844a |
12 | 128a8a0188b63b |
13 | 584526ba40b89 |
14 | 24656449444d9 |
15 | 102dd8c8abc6b |
hex | 7789ea98c5cf |
131434230105551 has 8 divisors (see below), whose sum is σ = 133931693376864. Its totient is φ = 128937417654240.
The previous prime is 131434230105527. The next prime is 131434230105569. The reversal of 131434230105551 is 155501032434131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131434230105551 - 218 = 131434229843407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131434230185551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 162297251 + ... + 163105076.
It is an arithmetic number, because the mean of its divisors is an integer number (16741461672108).
Almost surely, 2131434230105551 is an apocalyptic number.
131434230105551 is a deficient number, since it is larger than the sum of its proper divisors (2497463271313).
131434230105551 is an equidigital number, since it uses as much as digits as its factorization.
131434230105551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 325410001.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 131434230105551 its reverse (155501032434131), we get a palindrome (286935262539682).
The spelling of 131434230105551 in words is "one hundred thirty-one trillion, four hundred thirty-four billion, two hundred thirty million, one hundred five thousand, five hundred fifty-one".
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