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131442414137 is a prime number
BaseRepresentation
bin111101001101010010…
…1000001001000111001
3110120021110002110211122
41322122211001020321
54123143224223022
6140214523035025
712332160041246
oct1723245011071
9416243073748
10131442414137
11508208a8231
122158396ba75
13c519983918
14650cc9c5cd
1536447d5742
hex1e9a941239

131442414137 has 2 divisors, whose sum is σ = 131442414138. Its totient is φ = 131442414136.

The previous prime is 131442414127. The next prime is 131442414149. The reversal of 131442414137 is 731414244131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128682908176 + 2759505961 = 358724^2 + 52531^2 .

It is a cyclic number.

It is not a de Polignac number, because 131442414137 - 28 = 131442413881 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131442414097 and 131442414106.

It is not a weakly prime, because it can be changed into another prime (131442414127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65721207068 + 65721207069.

It is an arithmetic number, because the mean of its divisors is an integer number (65721207069).

Almost surely, 2131442414137 is an apocalyptic number.

It is an amenable number.

131442414137 is a deficient number, since it is larger than the sum of its proper divisors (1).

131442414137 is an equidigital number, since it uses as much as digits as its factorization.

131442414137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 32256, while the sum is 35.

Adding to 131442414137 its reverse (731414244131), we get a palindrome (862856658268).

The spelling of 131442414137 in words is "one hundred thirty-one billion, four hundred forty-two million, four hundred fourteen thousand, one hundred thirty-seven".