Base | Representation |
---|---|
bin | 11000011110111010… |
… | …10101001011011011 |
3 | 1020221001020000221221 |
4 | 30033131111023123 |
5 | 203404411432201 |
6 | 10012142512511 |
7 | 643504162543 |
oct | 141735251333 |
9 | 36831200857 |
10 | 13144249051 |
11 | 563564994a |
12 | 2669b95737 |
13 | 131623907b |
14 | 8c9998323 |
15 | 51de474a1 |
hex | 30f7552db |
13144249051 has 2 divisors, whose sum is σ = 13144249052. Its totient is φ = 13144249050.
The previous prime is 13144249037. The next prime is 13144249123. The reversal of 13144249051 is 15094244131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13144249051 - 223 = 13135860443 is a prime.
It is a super-2 number, since 2×131442490512 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13144248998 and 13144249016.
It is not a weakly prime, because it can be changed into another prime (13144249351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572124525 + 6572124526.
It is an arithmetic number, because the mean of its divisors is an integer number (6572124526).
Almost surely, 213144249051 is an apocalyptic number.
13144249051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13144249051 is an equidigital number, since it uses as much as digits as its factorization.
13144249051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 34.
The spelling of 13144249051 in words is "thirteen billion, one hundred forty-four million, two hundred forty-nine thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •