Base | Representation |
---|---|
bin | 11000011110111011… |
… | …01011101001101111 |
3 | 1020221001101201020021 |
4 | 30033131223221233 |
5 | 203404422403403 |
6 | 10012144503011 |
7 | 643505025115 |
oct | 141735535157 |
9 | 36831351207 |
10 | 13144341103 |
11 | 5635702023 |
12 | 266a01aa67 |
13 | 131626bc3a |
14 | 8c99bdab5 |
15 | 51de648bd |
hex | 30f76ba6f |
13144341103 has 4 divisors (see below), whose sum is σ = 13144622560. Its totient is φ = 13144059648.
The previous prime is 13144341097. The next prime is 13144341109. The reversal of 13144341103 is 30114344131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30114344131 = 349 ⋅86287519.
It is an interprime number because it is at equal distance from previous prime (13144341097) and next prime (13144341109).
It is a cyclic number.
It is not a de Polignac number, because 13144341103 - 25 = 13144341071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13144341109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52050 + ... + 170287.
It is an arithmetic number, because the mean of its divisors is an integer number (3286155640).
Almost surely, 213144341103 is an apocalyptic number.
13144341103 is a deficient number, since it is larger than the sum of its proper divisors (281457).
13144341103 is an equidigital number, since it uses as much as digits as its factorization.
13144341103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 281456.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13144341103 its reverse (30114344131), we get a palindrome (43258685234).
The spelling of 13144341103 in words is "thirteen billion, one hundred forty-four million, three hundred forty-one thousand, one hundred three".
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