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1314434130042 = 231119915668637
BaseRepresentation
bin10011001000001010011…
…000010010000001111010
311122122210011201020021010
4103020022120102001322
5133013430114130132
62443502005054350
7163651621521225
oct23101230220172
94578704636233
101314434130042
114674a2887790
121928b53b73b6
1396c486376a7
144789458c5bc
15242d120e6cc
hex1320a61207a

1314434130042 has 16 divisors (see below), whose sum is σ = 2867856283872. Its totient is φ = 398313372720.

The previous prime is 1314434129993. The next prime is 1314434130047. The reversal of 1314434130042 is 2400314344131.

It is a junction number, because it is equal to n+sod(n) for n = 1314434129991 and 1314434130009.

It is not an unprimeable number, because it can be changed into a prime (1314434130047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9957834253 + ... + 9957834384.

It is an arithmetic number, because the mean of its divisors is an integer number (179241017742).

Almost surely, 21314434130042 is an apocalyptic number.

1314434130042 is an abundant number, since it is smaller than the sum of its proper divisors (1553422153830).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1314434130042 is a wasteful number, since it uses less digits than its factorization.

1314434130042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19915668653.

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 1314434130042 its reverse (2400314344131), we get a palindrome (3714748474173).

The spelling of 1314434130042 in words is "one trillion, three hundred fourteen billion, four hundred thirty-four million, one hundred thirty thousand, forty-two".

Divisors: 1 2 3 6 11 22 33 66 19915668637 39831337274 59747005911 119494011822 219072355007 438144710014 657217065021 1314434130042