Base | Representation |
---|---|
bin | 1011111101000110100001… |
… | …1001111011111100000111 |
3 | 1201112120212110102022201210 |
4 | 2333101220121323330013 |
5 | 3210324112444232320 |
6 | 43542233131222503 |
7 | 2524435166520060 |
oct | 277215031737407 |
9 | 51476773368653 |
10 | 13144351555335 |
11 | 4208540864860 |
12 | 15835688a7a33 |
13 | 744678c4ac10 |
14 | 33629355b567 |
15 | 17bdac4230e0 |
hex | bf46867bf07 |
13144351555335 has 64 divisors (see below), whose sum is σ = 28237376240640. Its totient is φ = 5042388602880.
The previous prime is 13144351555301. The next prime is 13144351555393. The reversal of 13144351555335 is 53355515344131.
It is not a de Polignac number, because 13144351555335 - 27 = 13144351555207 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 437692330 + ... + 437722359.
It is an arithmetic number, because the mean of its divisors is an integer number (441209003760).
Almost surely, 213144351555335 is an apocalyptic number.
13144351555335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13144351555335 is an abundant number, since it is smaller than the sum of its proper divisors (15093024685305).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13144351555335 is a wasteful number, since it uses less digits than its factorization.
13144351555335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 875414728.
The product of its digits is 4050000, while the sum is 48.
Adding to 13144351555335 its reverse (53355515344131), we get a palindrome (66499866899466).
The spelling of 13144351555335 in words is "thirteen trillion, one hundred forty-four billion, three hundred fifty-one million, five hundred fifty-five thousand, three hundred thirty-five".
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