Base | Representation |
---|---|
bin | 11000011110111011… |
… | …01111010001100101 |
3 | 1020221001102110120211 |
4 | 30033131233101211 |
5 | 203404423342231 |
6 | 10012145055421 |
7 | 643505116303 |
oct | 141735572145 |
9 | 36831373524 |
10 | 13144355941 |
11 | 5635712192 |
12 | 266a027571 |
13 | 1316275912 |
14 | 8c99c5273 |
15 | 51de68eb1 |
hex | 30f76f465 |
13144355941 has 2 divisors, whose sum is σ = 13144355942. Its totient is φ = 13144355940.
The previous prime is 13144355923. The next prime is 13144355947. The reversal of 13144355941 is 14955344131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12576725316 + 567630625 = 112146^2 + 23825^2 .
It is a cyclic number.
It is not a de Polignac number, because 13144355941 - 217 = 13144224869 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13144355894 and 13144355903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13144355947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572177970 + 6572177971.
It is an arithmetic number, because the mean of its divisors is an integer number (6572177971).
Almost surely, 213144355941 is an apocalyptic number.
It is an amenable number.
13144355941 is a deficient number, since it is larger than the sum of its proper divisors (1).
13144355941 is an equidigital number, since it uses as much as digits as its factorization.
13144355941 is an evil number, because the sum of its binary digits is even.
The product of its digits is 129600, while the sum is 40.
The spelling of 13144355941 in words is "thirteen billion, one hundred forty-four million, three hundred fifty-five thousand, nine hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •