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1314440553253 is a prime number
BaseRepresentation
bin10011001000001010110…
…000110010001100100101
311122122210121210120020211
4103020022300302030211
5133013433240201003
62443502354455421
7163652030232622
oct23101260621445
94578717716224
101314440553253
114674a6474623
121928b7594571
1396c49a761c9
1447895381349
15242d1a7c96d
hex1320ac32325

1314440553253 has 2 divisors, whose sum is σ = 1314440553254. Its totient is φ = 1314440553252.

The previous prime is 1314440553221. The next prime is 1314440553287. The reversal of 1314440553253 is 3523550444131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1281147806884 + 33292746369 = 1131878^2 + 182463^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314440553253 - 25 = 1314440553221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314440553553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657220276626 + 657220276627.

It is an arithmetic number, because the mean of its divisors is an integer number (657220276627).

Almost surely, 21314440553253 is an apocalyptic number.

It is an amenable number.

1314440553253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314440553253 is an equidigital number, since it uses as much as digits as its factorization.

1314440553253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 1314440553253 its reverse (3523550444131), we get a palindrome (4837990997384).

The spelling of 1314440553253 in words is "one trillion, three hundred fourteen billion, four hundred forty million, five hundred fifty-three thousand, two hundred fifty-three".