Base | Representation |
---|---|
bin | 10011001000001010110… |
… | …011101000110101101101 |
3 | 11122122210200012120110101 |
4 | 103020022303220311231 |
5 | 133013433433120412 |
6 | 2443502422511101 |
7 | 163652036466652 |
oct | 23101263506555 |
9 | 4578720176411 |
10 | 1314441301357 |
11 | 4674a6935698 |
12 | 1928b7895491 |
13 | 96c49c78882 |
14 | 478954d7c29 |
15 | 242d1b79457 |
hex | 1320ace8d6d |
1314441301357 has 2 divisors, whose sum is σ = 1314441301358. Its totient is φ = 1314441301356.
The previous prime is 1314441301291. The next prime is 1314441301513. The reversal of 1314441301357 is 7531031444131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1101767221801 + 212674079556 = 1049651^2 + 461166^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314441301357 - 211 = 1314441299309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314441301057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657220650678 + 657220650679.
It is an arithmetic number, because the mean of its divisors is an integer number (657220650679).
Almost surely, 21314441301357 is an apocalyptic number.
It is an amenable number.
1314441301357 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314441301357 is an equidigital number, since it uses as much as digits as its factorization.
1314441301357 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 37.
Adding to 1314441301357 its reverse (7531031444131), we get a palindrome (8845472745488).
The spelling of 1314441301357 in words is "one trillion, three hundred fourteen billion, four hundred forty-one million, three hundred one thousand, three hundred fifty-seven".
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