Base | Representation |
---|---|
bin | 10011001000001010110… |
… | …111100001101001101011 |
3 | 11122122210202010100110002 |
4 | 103020022313201221223 |
5 | 133013434213223431 |
6 | 2443502500413215 |
7 | 163652051243126 |
oct | 23101267415153 |
9 | 4578722110402 |
10 | 1314442320491 |
11 | 4674a7471353 |
12 | 1928b80a720b |
13 | 96c4a244701 |
14 | 478956c13bd |
15 | 242d1ccb3cb |
hex | 1320ade1a6b |
1314442320491 has 2 divisors, whose sum is σ = 1314442320492. Its totient is φ = 1314442320490.
The previous prime is 1314442320479. The next prime is 1314442320539. The reversal of 1314442320491 is 1940232444131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1314442320491 - 230 = 1313368578667 is a prime.
It is a super-2 number, since 2×13144423204912 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1314442322491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657221160245 + 657221160246.
It is an arithmetic number, because the mean of its divisors is an integer number (657221160246).
Almost surely, 21314442320491 is an apocalyptic number.
1314442320491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314442320491 is an equidigital number, since it uses as much as digits as its factorization.
1314442320491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 38.
The spelling of 1314442320491 in words is "one trillion, three hundred fourteen billion, four hundred forty-two million, three hundred twenty thousand, four hundred ninety-one".
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