Base | Representation |
---|---|
bin | 11000011110111100… |
… | …00100011000101011 |
3 | 1020221001120212012102 |
4 | 30033132010120223 |
5 | 203404434124121 |
6 | 10012151004015 |
7 | 643505626352 |
oct | 141736043053 |
9 | 36831525172 |
10 | 13144442411 |
11 | 5635771151 |
12 | 266a06960b |
13 | 13162a6099 |
14 | 8c9a08999 |
15 | 51de8490b |
hex | 30f78462b |
13144442411 has 2 divisors, whose sum is σ = 13144442412. Its totient is φ = 13144442410.
The previous prime is 13144442393. The next prime is 13144442417. The reversal of 13144442411 is 11424444131.
It is a happy number.
13144442411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13144442411 - 218 = 13144180267 is a prime.
It is a super-4 number, since 4×131444424114 (a number of 42 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (13144442417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572221205 + 6572221206.
It is an arithmetic number, because the mean of its divisors is an integer number (6572221206).
Almost surely, 213144442411 is an apocalyptic number.
13144442411 is a deficient number, since it is larger than the sum of its proper divisors (1).
13144442411 is an equidigital number, since it uses as much as digits as its factorization.
13144442411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6144, while the sum is 29.
Adding to 13144442411 its reverse (11424444131), we get a palindrome (24568886542).
The spelling of 13144442411 in words is "thirteen billion, one hundred forty-four million, four hundred forty-two thousand, four hundred eleven".
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