Base | Representation |
---|---|
bin | 100111001011000… |
… | …1110010001110101 |
3 | 10101121100220100211 |
4 | 1032112032101311 |
5 | 10142444323001 |
6 | 334233105421 |
7 | 44400425242 |
oct | 11626162165 |
9 | 3347326324 |
10 | 1314448501 |
11 | 614a76683 |
12 | 308258271 |
13 | 17c4265a2 |
14 | c68025c9 |
15 | 7a5e6351 |
hex | 4e58e475 |
1314448501 has 2 divisors, whose sum is σ = 1314448502. Its totient is φ = 1314448500.
The previous prime is 1314448451. The next prime is 1314448523. The reversal of 1314448501 is 1058444131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1185080625 + 129367876 = 34425^2 + 11374^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314448501 - 211 = 1314446453 is a prime.
It is a super-2 number, since 2×13144485012 = 3455549723562294002, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314448591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657224250 + 657224251.
It is an arithmetic number, because the mean of its divisors is an integer number (657224251).
Almost surely, 21314448501 is an apocalyptic number.
It is an amenable number.
1314448501 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314448501 is an equidigital number, since it uses as much as digits as its factorization.
1314448501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
The square root of 1314448501 is about 36255.3237607941. The cubic root of 1314448501 is about 1095.4213264347.
The spelling of 1314448501 in words is "one billion, three hundred fourteen million, four hundred forty-eight thousand, five hundred one".
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