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131451425113 is a prime number
BaseRepresentation
bin111101001101100011…
…1011001000101011001
3110120022002001021120111
41322123013121011121
54123203031100423
6140215444124321
712332326451311
oct1723307310531
9416262037514
10131451425113
11508259a2318
12215869966a1
13c51b7ba268
146510166441
1536454b560d
hex1e9b1d9159

131451425113 has 2 divisors, whose sum is σ = 131451425114. Its totient is φ = 131451425112.

The previous prime is 131451425101. The next prime is 131451425129. The reversal of 131451425113 is 311524154131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96828635929 + 34622789184 = 311173^2 + 186072^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131451425113 is a prime.

It is not a weakly prime, because it can be changed into another prime (131451425153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65725712556 + 65725712557.

It is an arithmetic number, because the mean of its divisors is an integer number (65725712557).

Almost surely, 2131451425113 is an apocalyptic number.

It is an amenable number.

131451425113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131451425113 is an equidigital number, since it uses as much as digits as its factorization.

131451425113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7200, while the sum is 31.

Adding to 131451425113 its reverse (311524154131), we get a palindrome (442975579244).

The spelling of 131451425113 in words is "one hundred thirty-one billion, four hundred fifty-one million, four hundred twenty-five thousand, one hundred thirteen".