Base | Representation |
---|---|
bin | 10011001000100010010… |
… | …011010100001000011011 |
3 | 11122200211010220222102200 |
4 | 103020202103110020123 |
5 | 133020240340343430 |
6 | 2444005503301243 |
7 | 163664564121042 |
oct | 23104223241033 |
9 | 4580733828380 |
10 | 1314835481115 |
11 | 467689395792 |
12 | 1929a78aa823 |
13 | 96cb082cc30 |
14 | 478d19c5559 |
15 | 2430658d460 |
hex | 132224d421b |
1314835481115 has 96 divisors (see below), whose sum is σ = 2601694105920. Its totient is φ = 608532922368.
The previous prime is 1314835481111. The next prime is 1314835481117. The reversal of 1314835481115 is 5111845384131.
1314835481115 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 83 + 548 + 11 + 15 = 666.
It is not a de Polignac number, because 1314835481115 - 22 = 1314835481111 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is not an unprimeable number, because it can be changed into a prime (1314835481111) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 8706571 + ... + 8856299.
It is an arithmetic number, because the mean of its divisors is an integer number (27100980270).
Almost surely, 21314835481115 is an apocalyptic number.
1314835481115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1314835481115 is a deficient number, since it is larger than the sum of its proper divisors (1286858624805).
1314835481115 is a wasteful number, since it uses less digits than its factorization.
1314835481115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150653 (or 150650 counting only the distinct ones).
The product of its digits is 230400, while the sum is 45.
The spelling of 1314835481115 in words is "one trillion, three hundred fourteen billion, eight hundred thirty-five million, four hundred eighty-one thousand, one hundred fifteen".
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