Base | Representation |
---|---|
bin | 1011111101011011110001… |
… | …1000000010011100010010 |
3 | 1201120010120222001010202010 |
4 | 2333112330120002130102 |
5 | 3210422303124423442 |
6 | 43545015122403350 |
7 | 2525026425610512 |
oct | 277267430023422 |
9 | 51503528033663 |
10 | 13150055311122 |
11 | 420a9a8446a14 |
12 | 158469ab00556 |
13 | 745077832542 |
14 | 336674c93842 |
15 | 17c0e303eb9c |
hex | bf5bc602712 |
13150055311122 has 32 divisors (see below), whose sum is σ = 26310295088064. Its totient is φ = 4381654636800.
The previous prime is 13150055311117. The next prime is 13150055311123. The reversal of 13150055311122 is 22111355005131.
13150055311122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a self number, because there is not a number n which added to its sum of digits gives 13150055311122.
It is not an unprimeable number, because it can be changed into a prime (13150055311123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 241165222 + ... + 241219742.
It is an arithmetic number, because the mean of its divisors is an integer number (822196721502).
Almost surely, 213150055311122 is an apocalyptic number.
13150055311122 is an abundant number, since it is smaller than the sum of its proper divisors (13160239776942).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13150055311122 is a wasteful number, since it uses less digits than its factorization.
13150055311122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69354.
The product of its (nonzero) digits is 4500, while the sum is 30.
The spelling of 13150055311122 in words is "thirteen trillion, one hundred fifty billion, fifty-five million, three hundred eleven thousand, one hundred twenty-two".
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