Base | Representation |
---|---|
bin | 11101111001101111011110… |
… | …001000100001010111001111 |
3 | 122020122100201201210222202122 |
4 | 131321233132020201113033 |
5 | 114214140201041140413 |
6 | 1143411245433443155 |
7 | 36462244236225224 |
oct | 3571573610412717 |
9 | 566570651728678 |
10 | 131511330411983 |
11 | 389a3707584865 |
12 | 128bb93a5704bb |
13 | 584c6081b1582 |
14 | 246927a54794b |
15 | 1030da14ec108 |
hex | 779bde2215cf |
131511330411983 has 2 divisors, whose sum is σ = 131511330411984. Its totient is φ = 131511330411982.
The previous prime is 131511330411913. The next prime is 131511330412009. The reversal of 131511330411983 is 389114033115131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131511330411983 - 212 = 131511330407887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131511330411913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65755665205991 + 65755665205992.
It is an arithmetic number, because the mean of its divisors is an integer number (65755665205992).
Almost surely, 2131511330411983 is an apocalyptic number.
131511330411983 is a deficient number, since it is larger than the sum of its proper divisors (1).
131511330411983 is an equidigital number, since it uses as much as digits as its factorization.
131511330411983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 44.
The spelling of 131511330411983 in words is "one hundred thirty-one trillion, five hundred eleven billion, three hundred thirty million, four hundred eleven thousand, nine hundred eighty-three".
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