Base | Representation |
---|---|
bin | 100111001100011… |
… | …1001100001000001 |
3 | 10101122200112111011 |
4 | 1032120321201001 |
5 | 10143134244024 |
6 | 334300120521 |
7 | 44406406144 |
oct | 11630714101 |
9 | 3348615434 |
10 | 1315149889 |
11 | 615405639 |
12 | 308536141 |
13 | 17c610901 |
14 | c694605b |
15 | 7a6d4094 |
hex | 4e639841 |
1315149889 has 2 divisors, whose sum is σ = 1315149890. Its totient is φ = 1315149888.
The previous prime is 1315149887. The next prime is 1315149919. The reversal of 1315149889 is 9889415131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1266149889 + 49000000 = 35583^2 + 7000^2 .
It is an emirp because it is prime and its reverse (9889415131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1315149889 - 21 = 1315149887 is a prime.
Together with 1315149887, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1315149887) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657574944 + 657574945.
It is an arithmetic number, because the mean of its divisors is an integer number (657574945).
Almost surely, 21315149889 is an apocalyptic number.
It is an amenable number.
1315149889 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315149889 is an equidigital number, since it uses as much as digits as its factorization.
1315149889 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 311040, while the sum is 49.
The square root of 1315149889 is about 36264.9953674339. The cubic root of 1315149889 is about 1095.6161302519.
The spelling of 1315149889 in words is "one billion, three hundred fifteen million, one hundred forty-nine thousand, eight hundred eighty-nine".
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