Base | Representation |
---|---|
bin | 10011001000110101010… |
… | …000001000100010110001 |
3 | 11122201122022011122210121 |
4 | 103020311100020202301 |
5 | 133021413233224241 |
6 | 2444101221530241 |
7 | 164005504401025 |
oct | 23106520104261 |
9 | 4581568148717 |
10 | 1315153414321 |
11 | 4678318a86aa |
12 | 192a76273981 |
13 | 970316694a6 |
14 | 47921d06385 |
15 | 24324440ad1 |
hex | 132354088b1 |
1315153414321 has 2 divisors, whose sum is σ = 1315153414322. Its totient is φ = 1315153414320.
The previous prime is 1315153414291. The next prime is 1315153414327. The reversal of 1315153414321 is 1234143515131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 854025498225 + 461127916096 = 924135^2 + 679064^2 .
It is a cyclic number.
It is not a de Polignac number, because 1315153414321 - 231 = 1313005930673 is a prime.
It is not a weakly prime, because it can be changed into another prime (1315153414327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657576707160 + 657576707161.
It is an arithmetic number, because the mean of its divisors is an integer number (657576707161).
Almost surely, 21315153414321 is an apocalyptic number.
It is an amenable number.
1315153414321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315153414321 is an equidigital number, since it uses as much as digits as its factorization.
1315153414321 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21600, while the sum is 34.
Adding to 1315153414321 its reverse (1234143515131), we get a palindrome (2549296929452).
The spelling of 1315153414321 in words is "one trillion, three hundred fifteen billion, one hundred fifty-three million, four hundred fourteen thousand, three hundred twenty-one".
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