Base | Representation |
---|---|
bin | 11000011111110110… |
… | …01011111111010111 |
3 | 1020221120221200011010 |
4 | 30033323023333113 |
5 | 203413412410420 |
6 | 10013022343303 |
7 | 643630541061 |
oct | 141773137727 |
9 | 36846850133 |
10 | 13152075735 |
11 | 563a005187 |
12 | 267072ab33 |
13 | 1317a49646 |
14 | 8caa34731 |
15 | 51e9914e0 |
hex | 30fecbfd7 |
13152075735 has 32 divisors (see below), whose sum is σ = 21569006592. Its totient is φ = 6839409920.
The previous prime is 13152075719. The next prime is 13152075743. The reversal of 13152075735 is 53757025131.
It is not a de Polignac number, because 13152075735 - 24 = 13152075719 is a prime.
It is a super-2 number, since 2×131520757352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13152075693 and 13152075702.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1278382 + ... + 1288628.
It is an arithmetic number, because the mean of its divisors is an integer number (674031456).
Almost surely, 213152075735 is an apocalyptic number.
13152075735 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13152075735 is a deficient number, since it is larger than the sum of its proper divisors (8416930857).
13152075735 is a wasteful number, since it uses less digits than its factorization.
13152075735 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12383.
The product of its (nonzero) digits is 110250, while the sum is 39.
The spelling of 13152075735 in words is "thirteen billion, one hundred fifty-two million, seventy-five thousand, seven hundred thirty-five".
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