Base | Representation |
---|---|
bin | 100111001100100… |
… | …1001011100010111 |
3 | 10101122210211222101 |
4 | 1032121021130113 |
5 | 10143143341002 |
6 | 334301342531 |
7 | 44410100302 |
oct | 11631113427 |
9 | 3348724871 |
10 | 1315215127 |
11 | 61544a656 |
12 | 308567a47 |
13 | 17c634505 |
14 | c6961b39 |
15 | 7a6e8587 |
hex | 4e649717 |
1315215127 has 2 divisors, whose sum is σ = 1315215128. Its totient is φ = 1315215126.
The previous prime is 1315215119. The next prime is 1315215173. The reversal of 1315215127 is 7215125131.
It is a weak prime.
It is an emirp because it is prime and its reverse (7215125131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1315215127 - 23 = 1315215119 is a prime.
It is a super-2 number, since 2×13152151272 = 3459581660579252258, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1315215095 and 1315215104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1315215107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657607563 + 657607564.
It is an arithmetic number, because the mean of its divisors is an integer number (657607564).
Almost surely, 21315215127 is an apocalyptic number.
1315215127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315215127 is an equidigital number, since it uses as much as digits as its factorization.
1315215127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2100, while the sum is 28.
The square root of 1315215127 is about 36265.8948186861. The cubic root of 1315215127 is about 1095.6342459623.
The spelling of 1315215127 in words is "one billion, three hundred fifteen million, two hundred fifteen thousand, one hundred twenty-seven".
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